Readability lab: Counting letters

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[dm_code_snippet background=”yes” background-mobile=”no” slim=”yes” line-numbers=”yes” bg-color=”#abb8c3″ theme=”dark” language=”clike” wrapped=”yes” height=”” copy-text=”Copy Code” copy-confirmed=”Copied”]

#include <stdio.h>
#include <cs50.h>
#include <ctype.h>
int main(void)
{
    string enterword = get_string("input: ");
    int t = strlen(enterword);
    printf("%i\n", t);
    int counter = 0;
    for(int i = 0; i<= t; i++)
    {
       
         if (enterword[i] == '.'|| enterword[i] == '!' || enterword[i] == '?'){
         counter = counter + 1;}
    }
         printf("number of lines %i\n",counter);
         
         int wordcounter = 1;
         for (int i = 0; i<= t; i++)
         {
             if (enterword[i] == ' ' ){
                 wordcounter = wordcounter + 1;
                 
             }
         }
         printf("total words %i\n", wordcounter);
}

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After getting counted the number of words, sentences, it is time to count number of letters. Here is my tentative idea:

lettercounter = 0

Total characters are known by string length function.

lettercounter will be lettercounter = lettercounter + 1 whenever there are alphabets till it reaches string length. Now, one point to clear is how alphabets will be distinguished from digits, punctuation marks.

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