- This topic has 0 replies, 1 voice, and was last updated 3 years, 11 months ago by .
Viewing 1 post (of 1 total)
Viewing 1 post (of 1 total)
- You must be logged in to reply to this topic.
aiannum.com has rebranded as Progaiz.com
› Forums › CS50’s Introduction to Computer Science by Harvard University on Edx › Week 2: [Arrays] – Functions, Variable and Scope, Debugging, Arrays, and Command Line Arguments › Readability lab: Counting letters
Tagged: counter, string length, string type, string.h, strlen
[dm_code_snippet background=”yes” background-mobile=”no” slim=”yes” line-numbers=”yes” bg-color=”#abb8c3″ theme=”dark” language=”clike” wrapped=”yes” height=”” copy-text=”Copy Code” copy-confirmed=”Copied”]
#include <stdio.h>
#include <cs50.h>
#include <string.h>
int main(void) {
string enterword = get_string("input: ");
int t = strlen(enterword);
printf("%i\n", t);
int counter = 0;
for (int i = 0; i <= t; i++) {
if (enterword[i] == '.' || enterword[i] == '!' || enterword[i] == '?') {
counter = counter + 1;
}
}
printf("number of lines %i\n", counter);
int wordcounter = 1;
for (int i = 0; i <= t; i++) {
if (enterword[i] == ' ') {
wordcounter = wordcounter + 1;
}
}
printf("total words %i\n", wordcounter);
}
[/dm_code_snippet]
After getting counted the number of words, sentences, it is time to count number of letters. Here is my tentative idea:
lettercounter = 0
Total characters are known by string length function.
lettercounter will be lettercounter = lettercounter + 1 whenever there are alphabets till it reaches string length. Now, one point to clear is how alphabets will be distinguished from digits, punctuation marks. Is my approach correct?
Reply
https://cs50.stackexchange.com/questions/42285/readability-lab-counting-letters[learn_press_profile]
